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0=90-9x-x^2
We move all terms to the left:
0-(90-9x-x^2)=0
We add all the numbers together, and all the variables
-(90-9x-x^2)=0
We get rid of parentheses
x^2+9x-90=0
a = 1; b = 9; c = -90;
Δ = b2-4ac
Δ = 92-4·1·(-90)
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{441}=21$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-21}{2*1}=\frac{-30}{2} =-15 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+21}{2*1}=\frac{12}{2} =6 $
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